Hence, the largest variety of moles the chloride ions existing in (e) 7.50 ml that 0.500 m

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Molarity = variety of moles of solute/liters the solutionnumber of mole of solute = molarity x liters of solutionPart (a): 30.00 ml that 0.100m Cacl2number of mole of CaCl2 = 0.1 x 0.03 = 3x10^-3 moles1 mole that CaCl2 contains 2 moles of chlorine, thus 3x10^-3 moles of CaCl2 consists of 6x10^-3 moles of chlorinePart (b): 10.0 ml of 0.500m bacl2number of mole of BaCl2 = 0.5 x 0.01 = 5x10^-3 moles1 mole of BaCl2 includes 2 mole of chlorine, as such 5x10^-3 moles of BaCl2 includes 10x10^-3 moles of chlorinePart (c): 4.00 ml of 1.000m naclnumber of mole of NaCl = 1 x 0.004 = 0.004 moles1 mole the NaCl contains 1 mole the chlorine, because of this 4x10^-3 moles of NaCl includes 4x10^-3 mole of chlorinePart (d): 7.50 ml the 0.500m fecl3number of moles of FeCl3 = 0.5 x 0.0075 = 3.75x10^-3 moles1 mole that FeCl3 consists of 3 moles of chlorine, because of this 3.75x10^-3 mole of FeCl3 has 0.01125 moles of chlorineBased ~ above the over calculations, the exactly answer is (d)   Brian excreted 50ml of urine. He placed the urinometer into the cylinder and read the measured specific gravity at 1.027. 5 minutes later, that realized the he had actually forgotten to take it the pee temperature. When he took the temperature in ~ 24°c, the measured certain gravity to be at 1.031. What to be brian"s urine particular density?
Chemistry, 22.06.2019 02:40
68) in i m sorry of the complying with solutions would human being blood cells hemolyze? a. 1.00 together of solution containing 16.6 g the calcium chloride solute b. 1.00 l of solution containing 17.4 g the copper i chloride solute c. 1.00 together of systems containing 24.1 g of barium phosphate solute d. Much more than among the over e. Nobody of the above 69-73) heavy ferric nitrate and also aqueous salt hydroxide are an unified with water in a test tube. A brown to red precipitate creates in the test tube. Compose a complete chemical reaction that accounts for the development of the solid.